Timeline for Solution to the following functional equation
Current License: CC BY-SA 2.5
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 15, 2010 at 1:51 | comment | added | Haining Yu | Volterra equations seems a viable option. | |
| Oct 14, 2010 at 18:54 | comment | added | Alex R. | Looks like I screwed up. Perhaps it's still salvageable? | |
| Oct 14, 2010 at 17:38 | comment | added | Haining Yu | Thank you both for commenting. I tried to following the link provided and work my way bottom up. It turns out to be difficult (if still possible). The difficulty arises when the change of variable takes place. When you doa variable change, two things have to be met simutaneously: 1) the term for $f(\cdot)$ has to have contain one variable, but not two ($t$ and $x$), and 2) the integral range after the change of variable has to be something like $[\tau,\infty)$. It turns out that such change of variable is hard to find -- because of coefficient of 2 in the term $2t-\tau$. | |
| Oct 13, 2010 at 23:46 | comment | added | Willie Wong | There is a problem with you change of variables. The interior integral of the double integral cannot be just $\int_0^\infty$, it should be $\int_\tau^\infty$. So I think the solution you wrote down using Laplace transform is not correct. | |
| Oct 13, 2010 at 22:03 | history | edited | Alex R. | CC BY-SA 2.5 |
added 102 characters in body
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| Oct 13, 2010 at 21:36 | history | answered | Alex R. | CC BY-SA 2.5 |