Timeline for roots of a fourth degree polynomial function (Vieta) [closed]
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
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| Apr 20, 2022 at 12:33 | history | closed |
Emil Jeřábek Max Alekseyev abx Daniele Tampieri Steven Landsburg |
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| Apr 19, 2022 at 15:29 | answer | added | Carlo Beenakker | timeline score: 3 | |
| Apr 19, 2022 at 14:52 | comment | added | Max Alekseyev | Quartic equations are solved in radicals - e.g., see mathworld.wolfram.com/QuarticEquation.html | |
| Apr 19, 2022 at 14:45 | comment | added | toni_iva | This is a characteristic function of a matrix and i search for which $x$ the determinant is 0. | |
| Apr 19, 2022 at 14:43 | comment | added | toni_iva | I tried it and first thought that $(-b)(-c)(1-a)(1-d)$ is the decomposition, but it’s not correct, there are some additional terms in my function. Now i have no idea for another decomposition which fits. | |
| Apr 19, 2022 at 14:41 | history | edited | toni_iva | CC BY-SA 4.0 |
edited body
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| Apr 19, 2022 at 14:15 | comment | added | Beni Bogosel | Have you tried separating into multiple simpler polynomials? You can easily see that parts of the terms come from the decomposition of $(x+a)(x+b)(x+c)(x+d)$... From where does this question come from? | |
| Apr 19, 2022 at 12:55 | review | Close votes | |||
| Apr 20, 2022 at 12:40 | |||||
| Apr 19, 2022 at 12:07 | history | asked | toni_iva | CC BY-SA 4.0 |