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Apr 16, 2022 at 15:24 vote accept M.G.
Apr 14, 2022 at 21:21 comment added Max Alekseyev @M.G.: This problem does not require any advanced methods: connection with $f_n$ can be easily proved by induction on $n$, while the formula for the coefficients is computed "backwards" - first picking $a_n$ parentheses containing $x_n$ from the product, then $a_{n-1}$ parentheses containing $x_{n-1}$ etc. Given that the formula works well in noncommutative case, I'd not be surprised if Comtet mentioned that in his paper (but I did not check).
Apr 14, 2022 at 20:50 comment added M.G. Dear @Max Alekseyev, thank you very much for taking the time to write this down. I am not a combinatorialist, so I very much appreciate this. Do you know any good reference for the umbral methods you just employed, suitable for non-combinatorialists?
Apr 14, 2022 at 20:34 history answered Max Alekseyev CC BY-SA 4.0