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Apr 11, 2022 at 23:11 answer added Magma timeline score: 11
Apr 11, 2022 at 10:04 answer added Peter LeFanu Lumsdaine timeline score: 14
Apr 10, 2022 at 23:04 history became hot network question
Apr 10, 2022 at 21:18 comment added LSpice As the body suggests, @J.W.Tanner further suggested, and the asker confirmed, I edited the word 'not' into the title.
Apr 10, 2022 at 21:17 history edited LSpice CC BY-SA 4.0
Putting 'not' in title, per https://mathoverflow.net/questions/420094/polyomino-that-can-cover-an-arbitrarily-large-square-but-the-entire-plane#comment1078870_420094
Apr 10, 2022 at 20:41 comment added Magma You might be referring to the phrase "all but X", which is an old fixed phrase which is used as either "all except X" or "almost X", and you aren't allowed to separate the words "all" and "but" so the meaning of "all" must be implied in the first usage.
Apr 10, 2022 at 20:05 comment added trotzt Well I saw the use of such a phrase, without not. Maybe I got something mixed up idk
Apr 10, 2022 at 19:25 comment added trotzt @J.W.Tanner Yeah, not sure if this is ok, my english is not the best lol
Apr 10, 2022 at 19:22 comment added J. W. Tanner In the title, did you mean but not the entire plane?
Apr 10, 2022 at 17:42 vote accept trotzt
Apr 10, 2022 at 17:11 history edited YCor
edited tags
Apr 10, 2022 at 16:59 answer added Magma timeline score: 49
Apr 10, 2022 at 16:47 comment added trotzt So tile for which every method of tiling is inevitably terminating, and there infinitely many different such methods, that was my idea, kinda.
Apr 10, 2022 at 16:28 comment added trotzt @RolandBacher But can it be that each square has such a pattern that is a subpattern only in a finite number of larger squares?
Apr 10, 2022 at 15:15 review Close votes
Apr 12, 2022 at 17:00
Apr 10, 2022 at 15:06 comment added Roland Bacher That is not possible by a sort of compacity argument : Given a sequence of larger and larger tilings, extract a subsequence agreeing on larger and larger tilings and go to the limit.
Apr 10, 2022 at 15:06 comment added Joseph Van Name If $S_{n}$ is a tiling that covers the $2n\times 2n$ square centered at the origin, then since the space of tilings is compact, you can take a subsequence of $S_{n}$ that convergences to a tiling of the entire plane. This is just Konig's lemma.
S Apr 10, 2022 at 14:54 review First questions
Apr 10, 2022 at 17:07
S Apr 10, 2022 at 14:54 history asked trotzt CC BY-SA 4.0