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Apr 10, 2022 at 19:05 answer added jjcale timeline score: 3
Apr 10, 2022 at 16:10 comment added LSpice @CarloBeenakker, sure, and of course you are careful to say it that way in your answer. I was objecting to the claim that there is a unique vector $\Omega$, as in the body of the question.
Apr 10, 2022 at 15:30 comment added Carlo Beenakker @LSpice --- certainly, vectors that differ by a complex factor describe the same state, in that sense $\Omega$ is a unique state.
Apr 10, 2022 at 14:51 comment added LSpice The conditions that you have stated can pin down $\Omega$ at most only up to scaling—but I guess in quantum physics one often works in projective space rather than affine space anyway?
Apr 10, 2022 at 7:55 answer added Vladimir Dotsenko timeline score: 4
Apr 10, 2022 at 6:34 answer added Carlo Beenakker timeline score: 1
Apr 10, 2022 at 6:27 comment added user473423 Start with $N=1$ and use Jordan normal form. Then use induction. Note that the kernel of $A_{N+1}$ is preserved by $A_j$ and $A_j^*$ for $j\le N$. For the induction step use that the claim holds on the kernel of $A$.
Apr 10, 2022 at 2:23 history asked MathMath CC BY-SA 4.0