Skip to main content

Timeline for Uniformly convex Banach spaces

Current License: CC BY-SA 4.0

8 events
when toggle format what by license comment
Apr 26, 2022 at 0:26 history edited Piotr Hajlasz CC BY-SA 4.0
added 194 characters in body
Apr 16, 2022 at 22:46 answer added Onur Oktay timeline score: 2
Apr 10, 2022 at 22:17 comment added Bill Johnson If you have at hand the theory of ultra powers of Banach spaces, the result is very easy. It is trivial that the $p$-direct sum of two strictly convex spaces is strictly convex (here $1<p<\infty$) and it is equally easy that a Banach space is uniformly convex if and only if its ultra powers are strictly convex. The downside of this line of argument is that you do not get any estimate on the modulus of convexity of the direct sum if you know the modulus of convexity of the direct summands.
Apr 10, 2022 at 15:50 comment added Willie Wong @OnurOktay Maybe post it as an answer?
Apr 10, 2022 at 13:46 history edited Piotr Hajlasz CC BY-SA 4.0
added 158 characters in body
Apr 9, 2022 at 18:18 comment added Onur Oktay Professor @Hajlasz, the proof in doi.org/10.1016/s0022-247x(02)00282-2 is a bit lengthy but self-involved & straightforward in a way that one may even consider to suggest it for advanced undergrad or novice grad students. I hope you find it useful.
Apr 9, 2022 at 14:06 history edited Piotr Hajlasz CC BY-SA 4.0
added 98 characters in body
Apr 9, 2022 at 13:26 history asked Piotr Hajlasz CC BY-SA 4.0