Timeline for One-step problems in geometry
Current License: CC BY-SA 4.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 8, 2022 at 20:21 | comment | added | Z. M | I am not smart enough to come up with this solution but I have a very naive way to attack this: for every $u\in\mathbb C$, let $S_u$ denote the set of complex numbers $z$ of modulus $1$ such that $\lvert 2u-z\rvert=1$. Then the cardinality of $S_u$ is at most $2$ if $u\neq0$, and $S_{-u}$ is symmetric to $S_u$ with respect to $0$. The result then follows. An obvious geometric interpretation of $S_u$: it is the intersection of the unit circle and the line passing through $u$ and perpendicular to $u-0$. | |
| Apr 7, 2022 at 8:48 | review | Late answers | |||
| Apr 7, 2022 at 9:22 | |||||
| S Apr 7, 2022 at 8:30 | review | First answers | |||
| Apr 7, 2022 at 8:37 | |||||
| S Apr 7, 2022 at 8:30 | history | answered | Samuel Adrian Antz | CC BY-SA 4.0 | |
| S Apr 7, 2022 at 8:30 | history | made wiki | Post Made Community Wiki by Samuel Adrian Antz |