Timeline for Is the class of DTI-groups closed under taking quotients?
Current License: CC BY-SA 4.0
10 events
| when toggle format | what | by | license | comment | |
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| S Apr 25, 2022 at 16:03 | history | bounty ended | CommunityBot | ||
| S Apr 25, 2022 at 16:03 | history | notice removed | CommunityBot | ||
| S Apr 17, 2022 at 14:43 | history | bounty started | Leyli Jafari | ||
| S Apr 17, 2022 at 14:43 | history | notice added | Leyli Jafari | Draw attention | |
| Apr 6, 2022 at 7:57 | history | edited | Leyli Jafari | CC BY-SA 4.0 |
added 7 characters in body
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| Apr 6, 2022 at 1:28 | comment | added | Leyli Jafari | @zibadawa timmy $K'$ is TI in $G$. I.e. the derived subgroup of every subgroup of $G$ is a TI-subgroup of $G$. | |
| Apr 6, 2022 at 1:05 | comment | added | zibadawa timmy | If $H$ is a subgroup of $G$, and $K$ is a subgroup of $H$, is your definition wanting $K'$ to be TI in $G$ or $H$? | |
| Apr 5, 2022 at 19:10 | comment | added | Stefan Kohl♦ | An immediate observation is that the class of DTI-groups is closed under taking subgroups. | |
| Apr 5, 2022 at 18:02 | history | edited | YCor | CC BY-SA 4.0 |
fixed English
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| Apr 5, 2022 at 17:28 | history | asked | Leyli Jafari | CC BY-SA 4.0 |