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Gerald Edgar
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$ \varlimsup_{x\rightarrow 0^+}\frac{f(x)}{x^a}=\varliminf_{\deltax \rightarrow 0^+}\frac{f(x)}{x^a} $

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Gerald Edgar
  • 41.1k
  • 5
  • 125
  • 219

$f(x)$ is continuous for $\forall x \geq 0$ and monotonically decrease. $f(0)=0$. $a>0$. Is it true $$ \varlimsup_{x\rightarrow 0^+}\frac{f(x)}{x^a}=\varliminf_{\delta \rightarrow 0^+}\frac{f(x)}{x^a} $$$$ \varlimsup_{x\rightarrow 0^+}\frac{f(x)}{x^a}=\varliminf_{x \rightarrow 0^+}\frac{f(x)}{x^a} $$ whenever both are finite or infinite?

$f(x)$ is continuous for $\forall x \geq 0$ and monotonically decrease. $f(0)=0$. $a>0$. Is it true $$ \varlimsup_{x\rightarrow 0^+}\frac{f(x)}{x^a}=\varliminf_{\delta \rightarrow 0^+}\frac{f(x)}{x^a} $$ whenever both are finite or infinite?

$f(x)$ is continuous for $\forall x \geq 0$ and monotonically decrease. $f(0)=0$. $a>0$. Is it true $$ \varlimsup_{x\rightarrow 0^+}\frac{f(x)}{x^a}=\varliminf_{x \rightarrow 0^+}\frac{f(x)}{x^a} $$ whenever both are finite or infinite?

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Watheophy
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A limit about continuous and monotonic decrease functions $ \varlimsup_{x\rightarrow 0^+}\frac{f(x)}{x^a}=\varliminf_{\delta \rightarrow 0^+}\frac{f(x)}{x^a} $

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Watheophy
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