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Mar 29, 2023 at 10:52 comment added ahdahmani @Guest You are not quoting correctly, in fact, uniform continuous isn't the same as immediately uniform continuous, the same for diffierentiable.
Apr 18, 2022 at 5:23 comment added S. Maths @DenisSerre he talked about "$C_0$-sg" not just "sg"..
Apr 2, 2022 at 19:46 comment added Guest @DenisSerre I follow the standard monograph of Engel and Nagel where Diagram II.4.26 says that every analytic $C_0$-semigroup is (immediately) norm continuous.
Apr 2, 2022 at 19:40 comment added Denis Serre @Guest. An analytic semi-group is a sg defined for $z$ beloging to an open sector of the complex plane. This does not imply that the sg be norm-continuous. Example: the heat semi-group.
Apr 2, 2022 at 19:17 comment added Guest @DenisSerre No, I say an "analytic" $C_0$-semigroup is differentiable.
Apr 2, 2022 at 19:15 comment added Denis Serre @Guest You say that a $C^0$-sg is differentiable, and that a differentiable sg is norm-continuous. Thus you imply that a $C^0$-sg is norm-continuous. Don't you ?
Apr 2, 2022 at 19:13 comment added Guest @GiorgioMetafune Thanks!
Apr 2, 2022 at 19:13 comment added Guest @DenisSerre But I never said that they are?
Apr 2, 2022 at 9:59 comment added Denis Serre Something is wrong in your premisses, since $C^0$-semigroup are not necessarily norm-continuous.
Apr 2, 2022 at 9:17 history edited Daniele Tampieri CC BY-SA 4.0
Typo fixed
Apr 2, 2022 at 8:08 comment added Giorgio Metafune The answer is yes and you find it in any book on semigroups. In few words we may define $e^{zA} $ by a power series.
Apr 2, 2022 at 7:01 history asked Guest CC BY-SA 4.0