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when toggle format what by license comment
Apr 2, 2022 at 15:14 comment added Anton Petrunin @Carlos_Petterson then you should say "global" somewhere in your question, otherwise it is unclear.
Apr 2, 2022 at 12:15 comment added Carlos_Petterson The Nash-Kuiper theorem provides an isometric embedding (in the Riemannian sense) and not in the metric sense (as YCor pointed out to me a couple of days ago). So then $f:\mathbb{H}^n \rightarrow \mathbb{R}^{2n+1}$ is only locally Lipschitz with constant $\max_{x\in ...}\,\|\nabla f(x)\|\neq 1$.
Apr 1, 2022 at 16:30 history answered Anton Petrunin CC BY-SA 4.0