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Mar 30, 2022 at 13:25 vote accept user1868607
Mar 30, 2022 at 13:13 answer added Emil Jeřábek timeline score: 5
Mar 30, 2022 at 12:50 comment added user1868607 I see @EmilJeřábek I overlooked then that that's equivalent to Presburger feel free to post it as an answer.
Mar 30, 2022 at 12:48 comment added Emil Jeřábek My German is a bit rusty, but reviews of Skolem’s paper (Gödel, Ackermann) indicate that it does, indeed, prove quantifier elimination for Presburger arithmetic (albeit in a somewhat unusual language, including function symbols for multiplication by rational constants and $\lfloor x\rfloor$, so apparently the values of terms may be rationals, even though variables range over integers).
Mar 30, 2022 at 10:51 history asked user1868607 CC BY-SA 4.0