Timeline for Group which "resembles" the free product of a cyclic group of order two and a cyclic group of order three, but isn't.
Current License: CC BY-SA 4.0
11 events
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| Oct 19, 2018 at 21:25 | history | edited | user6976 | CC BY-SA 4.0 |
a misprint fixed
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| Oct 13, 2010 at 1:54 | comment | added | user6976 | @Todd: No problem. I just wanted to refresh my understanding of the class of (2,3)-groups. | |
| Oct 12, 2010 at 22:26 | comment | added | Todd Trimble | Sorry to have to eat my words, Mark. I appreciate the time you put into this, and I wish I could accept your answer as well. But Derek Holt's solution was a bit easier for me to follow. | |
| Oct 12, 2010 at 22:12 | history | edited | user6976 | CC BY-SA 2.5 |
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| Oct 12, 2010 at 22:00 | history | edited | user6976 | CC BY-SA 2.5 |
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| Oct 12, 2010 at 19:35 | comment | added | Todd Trimble | These look like serious contenders in your update, Mark -- thanks very much! I didn't know about Thompson's group $V$, and I would have to do some reading up here to convince myself. But I'm on the verge of accepting this as an answer. | |
| Oct 12, 2010 at 18:43 | history | edited | user6976 | CC BY-SA 2.5 |
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| Oct 12, 2010 at 18:32 | comment | added | user6976 | @Andreas: No, one can use the fact that PSL(2,Z) is "large" (that is it has finite index free subgroup). Then by an old result of Pride (?) it is SQ-universal. | |
| Oct 12, 2010 at 18:29 | comment | added | Andreas Thom | Does one need the full force of Olshanskii's result? | |
| Oct 12, 2010 at 18:29 | comment | added | Todd Trimble | That's very interesting Mark (and thank you), but an explicit example would be very nice. Explicit geometric examples would be most welcome! | |
| Oct 12, 2010 at 18:24 | history | answered | user6976 | CC BY-SA 2.5 |