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Mar 30, 2022 at 9:24 answer added Dirk timeline score: 2
Mar 30, 2022 at 9:21 comment added Denis Serre The inverse must be an unbounded operator, hopefully densely defined. Actually, since $K$ is continuous, $F$ is a compact operatpr (all called a completely continuous operator ?) over $C(V)$.
Mar 30, 2022 at 9:10 history edited MikeTeX CC BY-SA 4.0
added 12 characters in body
Mar 30, 2022 at 9:03 history asked MikeTeX CC BY-SA 4.0