Skip to main content
5 events
when toggle format what by license comment
Mar 29, 2022 at 20:35 comment added Maxime Ramzi First, contravariantly it is never an equivalence except in trivial cases - this is because a category cannot be presentable and have its opposite be presentable too without being a preorder or something. Second, your statement in classical Morita theory is wrong (think about $A= B = \mathbb Z, X= \mathbb Z^n$), you need this condition + something about endomorphism rings. The same kind of criterion holds in this $\infty$-word by replacing "finitely generated projective" with "compact" or equivalently "perfect"
Mar 29, 2022 at 19:00 comment added curious math guy Can I ask a follow-ups? In the "classical" Morita theory, we know that $-\otimes X$ is an equivalence iff $X$ is a finitely generated projective generator (when view as $A$ and $B$-module respectively). Do we have a similar criterion here in the stable-infinity case and contravariantly?
Mar 29, 2022 at 16:27 comment added curious math guy I think this is a wonderful answer, thanks!
Mar 29, 2022 at 16:26 vote accept curious math guy
Mar 29, 2022 at 14:30 history answered Maxime Ramzi CC BY-SA 4.0