Timeline for A question about average deviation of given $n$ complex numbers
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
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| Mar 31, 2022 at 6:18 | vote | accept | AgnostMystic | ||
| Mar 29, 2022 at 14:19 | comment | added | AgnostMystic | Thank you for your edifying comment.Valuable Advice noted! | |
| Mar 29, 2022 at 13:59 | comment | added | Iosif Pinelis | Previous comment continued: Try not to use vague terms such as "general points"; use quantifiers "for all/any" and "there exist(s)" instead. | |
| Mar 29, 2022 at 13:59 | comment | added | Iosif Pinelis | @sajjadveeri : You asked if for any $n$ points in the unit disk there is some $z$ in the unit disk with $f(z)=|z|$. My answer proves that this is not true; that is, for some $n$ points in the unit disk there is no $z$ in the unit disk with $f(z)=|z|$. If you had asked if for some $n$ points in the unit disk there is some $z$ in the unit disk with $f(z)=|z|$, then the answer would have trivially been yes -- by letting e.g. $z_j=0$ for all $j$ and then choosing $z=0$. I hope you can understand this logic. | |
| Mar 29, 2022 at 13:36 | comment | added | AgnostMystic | @losif Pinels ,you have taken the points on the unit circle and not general points in the unit disc.Could you kindly clarify ? | |
| Mar 29, 2022 at 5:19 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
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| Mar 29, 2022 at 4:52 | history | edited | Iosif Pinelis | CC BY-SA 4.0 |
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| Mar 28, 2022 at 17:41 | history | answered | Iosif Pinelis | CC BY-SA 4.0 |