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Mar 30, 2022 at 12:49 vote accept Dapao Zhang
Mar 30, 2022 at 12:49
Mar 30, 2022 at 12:16 answer added Dapao Zhang timeline score: 0
Mar 30, 2022 at 7:55 answer added pavel timeline score: 2
Mar 28, 2022 at 17:22 comment added Christian Remling When $f=1$, this works because of the decay of $\widehat{\sigma}$, which is perhaps restating what Willie already said above. (Or it's completely unhelpful since this doesn't give one any idea what one would do with a very irregular $f$.)
Mar 28, 2022 at 15:35 history edited Dapao Zhang CC BY-SA 4.0
Add an idea using Fourier restriction.
Mar 28, 2022 at 2:12 comment added Dapao Zhang Those $f$ may be considered as distributions supported on the sphere, as the inequality says.
Mar 28, 2022 at 0:37 comment added paul garrett For the questioner: do you extend functions from the sphere to the ambient Euclidean spaces by degree-zero homogeneity? Or just to consider them as distributions supported on the sphere? Could you clarify?
Mar 28, 2022 at 0:29 comment added Willie Wong IIRC how spherical harmonics transform under Fourier transform is discussed in Stein & Weiss, Introduction for Fourier Analysis on Euclidean Spaces (Chapter 4). But the sort of decay results that guarantees embedding into $H^{-s}$ are more related to Fourier restriction theorems, and I don't think the spherical harmonics expansion help that much.
Mar 27, 2022 at 19:01 history edited Daniele Tampieri CC BY-SA 4.0
Minor Math Jaxing and formatting
Mar 27, 2022 at 17:12 comment added Daniel Shapero Maybe the wiki on plane wave expansion is helpful here? + some asymptotics of Bessel functions
Mar 27, 2022 at 15:58 history asked Dapao Zhang CC BY-SA 4.0