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Mar 29, 2022 at 13:49 comment added Arshak Aivazian @SeverinBunk Thank you very much for the link to this book! I have long been interested in synthetic differential geometry - I think now that this is the best approach. But unfortunately it doesn't help me now -- see this comment of mine (correct me if I'm wrong)
Mar 29, 2022 at 7:45 comment added Severin Bunk I am not aware of a "nice" embedding functor of diffeological spaces into locally ringed spaces. However, maybe you find the framework of $C^\infty$-rings and locally $C^\infty$-ringed spaces helpful; see, for instance, the book "Smooth infinitesimal analysis" by Moerdijk and Reyes, as well as Dominic Joyce's arxiv.org/abs/1001.0023v7.
Mar 28, 2022 at 14:02 comment added Simon Henry Essentially yes. I wouldn't say it "shows" because the question didn't really specify how you build a locally ringed space out of a diffeological spaces - but at least it shows that Naive constructions using smooth function don't distinguish between the different non-commutative torus (or Irrational if you prefer). It is different from the discrete space though : the discrete space has plenty of non-constant smooth functions on it.
Mar 28, 2022 at 11:59 comment added Konrad Waldorf @SimonHenry: Ok, now I see your point. The irrational torus has only constant smooth functions and has the discrete D-topology. Hence, it can not be distinguished from the discrete torus as locally ringed spaces. However, it is not diffeomorphic to the discrete torus. This shows that the functor is not full. Correct?
Mar 28, 2022 at 11:39 comment added Konrad Waldorf And did you mean the "irrational" torus instead of "non-commutative"? Because the D-topology of the irrational torus is discrete, so it seems to fit very well that it doesn't have non-constant smooth functions.
Mar 28, 2022 at 11:32 comment added Simon Henry I mean't no non-constant smooth functions to $\mathbb{R}$.
Mar 28, 2022 at 11:24 comment added Konrad Waldorf @SimonHenry: what do you mean by "have no smooth function defined on them"? Every diffeological space has smooth functions, for example all constant ones.
Mar 26, 2022 at 23:12 comment added Arshak Aivazian @SimonHenry Thanks! In fact, I'm looking for a small extension of the category of smooth manifolds to include the important naturally occurring infinite-dimensional manifolds (such as spaces of smooth functions), but still being a full subcategory of locally ringed spaces. Apparently, diffiological spaces are not suitable for my purposes. Now I asked this question separately.
Mar 26, 2022 at 20:11 comment added Simon Henry Almost certainly not. Diffelofical strucutre can capture very singular spaces, like the non-commutative torus, that have no smooth function defined on them. I really don't see a way to attach to them a locally ringed space in a way that capture any interesting information
Mar 26, 2022 at 19:34 history edited Arshak Aivazian CC BY-SA 4.0
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Mar 26, 2022 at 19:21 history asked Arshak Aivazian CC BY-SA 4.0