Timeline for Zero trace elements in finite fields
Current License: CC BY-SA 4.0
6 events
| when toggle format | what | by | license | comment | |
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| Mar 24, 2022 at 22:32 | history | edited | Sean Eberhard | CC BY-SA 4.0 |
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| Mar 24, 2022 at 15:14 | comment | added | Sean Eberhard | I missed the restriction that $y$ should be in a subfield. | |
| Mar 24, 2022 at 15:13 | comment | added | Sean Eberhard | @PabloSpiga I said "more generally", because the situation you describe has needless restrictions. Read the first paragraph of my answer with $q$ replaced by $q^2$ and assume $n$ is prime if you want. | |
| Mar 24, 2022 at 15:05 | comment | added | Pablo Spiga | sorry, but there is something I do not understand, the trace map in my case has domain $\mathbb{F}_{q^{2n}}$ and not $\mathbb{F}_{q^n}$. The element $a$ is required to lie in a subgroup having order $(q^n+1)/(q+1)$, which is relatively prime to the order of the multiplicative group of $\mathbb{F}_{q^n}$. The element $y$ instead is restricted to be in $\mathbb{F}_{q^n}$, | |
| Mar 24, 2022 at 15:02 | history | edited | Sean Eberhard | CC BY-SA 4.0 |
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| Mar 24, 2022 at 14:50 | history | answered | Sean Eberhard | CC BY-SA 4.0 |