Timeline for Solving linear matrix equation
Current License: CC BY-SA 4.0
10 events
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Apr 24, 2022 at 18:44 | answer | added | loup blanc | timeline score: 0 | |
Mar 25, 2022 at 19:25 | comment | added | Wijdan Mt | here are the values of the first iteration: L = [-8 1.0231e-14 ; 1.0230e-14 -3.0184e-07 ], C = [0.5000 0; 0 0.5000; 1.0000 0; 0 1.0000 ; 1.0000 0; 0 1.0000] ; B = [0.1964 0.9805 0 0 0 0; -1.9046e-04 3.8145e-05 0 0 0 0] ; A =[ 0.1964 0.9805 0 0 0 0; -1.9046e-04 3.8145e-05 0 0 0 0] Note that, when I compute L it is shown too closely to be symmetric. | |
Mar 25, 2022 at 17:39 | history | edited | Rodrigo de Azevedo |
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Mar 25, 2022 at 17:03 | comment | added | Wijdan Mt | According to the author: yes X is normally a diagonal matrix. | |
Mar 25, 2022 at 7:41 | comment | added | Federico Poloni | @markvs I don't think you can assume that $X$ is diagonal, are you sure? If you're planning to change basis (with an unknown matrix $Q$), then you won't know the expression of the coefficients in that basis. | |
Mar 24, 2022 at 18:16 | answer | added | Federico Poloni | timeline score: 4 | |
Mar 24, 2022 at 15:04 | history | edited | Rodrigo de Azevedo | CC BY-SA 4.0 |
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Mar 24, 2022 at 14:27 | review | Close votes | |||
Mar 28, 2022 at 13:31 | |||||
S Mar 24, 2022 at 13:56 | review | First questions | |||
Mar 24, 2022 at 15:05 | |||||
S Mar 24, 2022 at 13:56 | history | asked | Wijdan Mt | CC BY-SA 4.0 |