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Mar 18, 2022 at 10:11 comment added Tibeku @GiorgioMetafune Thanks for your help so much! Is it still true for an elliptic operator $L$ in divergence form?
Mar 16, 2022 at 22:01 comment added Giorgio Metafune For convex sets and a general pure second order operator $L$ the same argument as above applies, since $d$ is concave and then $Ld \leq 0$.
Mar 16, 2022 at 8:54 comment added Tibeku @GiorgioMetafune Thanks for your answer so much! May I ask one more question? Does this conclusion still hold for domain diffeomorphic to a convex polyhedron (esp, in dim 2 diffeomorphic to a plane sector)? Or dose this conclustion hold in convex domain for variable coefficient elliptic operator rather than only the laplacian operator $\Delta$?
Mar 11, 2022 at 14:56 comment added Giorgio Metafune This should be true. If $\Omega$ is convex, then $\Delta d$ is concave (see mathoverflow.net/questions/291308/…). If $\Omega$ is also smooth, this implies $\Delta d \leq 0$ and then $d_t-\Delta d \geq 0$. The maximum principle for the heat equation gives $|u(t,x)| \leq Cd(x)$. This estimate does not depend on smoothness if $\Omega$ is convex and should give the result by some approximation, I guess.
Mar 11, 2022 at 13:37 comment added Tibeku @GiorgioMetafune Thank you so much for your help! May I ask one more question? Lemma 4.6.1 in book Heat kernels and spectral theory requires the domain to be $C^2$ and Lemma 4.6.1 does not hold in non-smooth domain. Do you think in convex polyhedron domain case there still holds: if $|u_0(x)|\leq C_0d(x)$, then $|u(t,x)|\leq Cd(x)$ where constant $C$ independent of $t$?
Mar 11, 2022 at 13:06 comment added Giorgio Metafune Yes, sure. The first eigenfunction is positive in the interior, so any estimate near the boundary extends to a global estimate, enlarging the constant $C$.
Mar 11, 2022 at 12:47 comment added Tibeku @GiorgioMetafune Thanks for your answer so much! It has been really helpful for me. Could you explain moreover, why my assumption is equivalent to $|u_0(x)|\leq C\phi(x)$, since here I only assume $|u_0(x)|\leq C{\rm dist}(x,\partial\Omega)$ when $x$ is sufficiently near the boundary.
Mar 11, 2022 at 10:01 comment added Giorgio Metafune Your assumption is equivalent to saying that $|u_0(x)| \leq C\phi(x)$, where $\phi$ is the first eigenfuntion. Then $|u(t,x)| \leq Ce^{-\lambda t}\phi(x)$, with $\lambda>0$ the first eigenvalue. For the boudary nehaviour of $\phi$ see for example Lemma 4.6.1, Heat kernels and spectral theory by Davies.
S Mar 11, 2022 at 9:05 review First questions
Mar 11, 2022 at 10:48
S Mar 11, 2022 at 9:05 history asked Tibeku CC BY-SA 4.0