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Apr 18, 2023 at 11:47 answer added Ben McKay timeline score: 1
S Mar 23, 2022 at 10:03 history bounty ended CommunityBot
S Mar 23, 2022 at 10:03 history notice removed CommunityBot
Mar 22, 2022 at 22:02 answer added Chris Wendl timeline score: 2
Mar 16, 2022 at 19:24 answer added Peter Michor timeline score: 1
S Mar 15, 2022 at 8:10 history bounty started Chris Wendl
S Mar 15, 2022 at 8:10 history notice added Chris Wendl Improve details
Mar 11, 2022 at 17:20 comment added Chris Wendl I would say the most natural topology on Diff(M) in this situation is $C^\infty_{loc}$, i.e. uniform convergence of all derivatives on compact subsets. For G this will of course be equivalent to the topology that it inherits from its identification with an orbit in M.
Mar 11, 2022 at 13:37 comment added Tobias Diez What topology do you want to consider on $Diff(M)$ if $M$ is not closed?
Mar 11, 2022 at 13:36 comment added Tobias Diez I don't have time right now for a detailed answer, so only a few observations for now. In arxiv.org/abs/1501.06269, section II.2 (especially Corollary II.2.3) the Lie group structure of a normal subgroup is extended to a Lie group structure on the ambient group. This seems to correspond to your basic lemma. Moreover, the proof of Theorem IV.4.16 seems to follow very closely the strategy you have outlined above (but of course here $G=Diff$ is not a Banach Lie group).
Mar 9, 2022 at 14:26 answer added Nicolast timeline score: 2
Mar 9, 2022 at 13:39 history asked Chris Wendl CC BY-SA 4.0