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Mar 10, 2022 at 0:15 comment added Will Sawin @Carl-FredrikNybergBrodda I think Bate-Gullon also include in their assumptions "Suppose that $\mathbb F_q$ is a splitting field for $A$."
Mar 9, 2022 at 23:40 history edited Dr. Evil CC BY-SA 4.0
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Mar 9, 2022 at 23:39 comment added LSpice Names of @Carl-FredrikNybergBrodda's references: Chigira, Takegahara, and Yoshida - On the Number of Homomorphisms from a Finite Group to a General Linear Group; Liebeck and Shalev - The Number of Homomorphisms from a Finite Group to a General Linear Group.
Mar 9, 2022 at 23:38 history edited Dr. Evil CC BY-SA 4.0
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Mar 9, 2022 at 23:35 history edited LSpice CC BY-SA 4.0
Names of papers; PDF -> abs; TeX
Mar 9, 2022 at 23:30 comment added Dr. Evil Thanks all for pointing out my fallacy. I have put in an edit at the end of the question relaxing the requirements.
Mar 9, 2022 at 23:29 history edited Dr. Evil CC BY-SA 4.0
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Mar 9, 2022 at 10:24 comment added Jeremy Rickard @Carl-FredrikNybergBrodda At the beginning of the "Preliminaries" section of Bate-Gullon, they say that their standing assumptions include that the order of the group is not divisible by the characteristic of the field.
Mar 9, 2022 at 9:54 history edited YCor CC BY-SA 4.0
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Mar 9, 2022 at 9:44 comment added Carl-Fredrik Nyberg Brodda (...cont) But then Bate-Gullon claims to prove things about the leading term of $c_n(q)$, which is not defined in the excluded case at all (such as observed by David E Speyer)! Either I am, or Bate-Gullon are, somewhat confused here; maybe I am misreading something.
Mar 9, 2022 at 9:43 comment added Carl-Fredrik Nyberg Brodda It's strange. The Bate-Gullon article (linked in the question) claims that $c_n(q)$ (which they denote $X(n,q)$ is always a polynomial. But their reference for this is this article, specifically Proposition~4.1, and that article has the condition that (in OP's notation) $|\Gamma|$ is not a multiple of $p$, where $q = p^k$. The article also references this article, which deals with that excluded case by giving polynomial bounds on $c_n(q)$, but doesn't claim that it's polynomial. (cont...)
Mar 9, 2022 at 9:29 comment added David E Speyer This is not a polynomial when $\Gamma$ is a cyclic group of order $k$ and $n=1$; the formula is $\text{GCD}(k, q-1)$. Perhaps you want to ask for a quasi-polynomial? en.wikipedia.org/wiki/Quasi-polynomial
Mar 9, 2022 at 9:20 history asked Dr. Evil CC BY-SA 4.0