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Let $R$ be a commutative Noetherian ring and $I$, $J$ be two ideal of $R$. If $x\in R$, then is $((I+J):x)=(I:x)+(J:x)$?

I would be very grateful if someone comment me.

Let $R$ be a commutative Noetherian ring and $I$, $J$ be two ideal of $R$. If $x\in R$, then is $((I+J):x)=(I:x)+(J:x)$.

Let $R$ be a commutative Noetherian ring and $I$, $J$ be two ideal of $R$. If $x\in R$, then is $((I+J):x)=(I:x)+(J:x)$?

I would be very grateful if someone comment me.

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Annihilators of sum of two ideals

Let $R$ be a commutative Noetherian ring and $I$, $J$ be two ideal of $R$. If $x\in R$, then is $((I+J):x)=(I:x)+(J:x)$.