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Mar 4, 2022 at 12:49 vote accept Ândson josé
Mar 4, 2022 at 12:33 history edited Farmer S CC BY-SA 4.0
corrected spelling (Mostowski)
Mar 4, 2022 at 12:13 comment added Asaf Karagila @Ândsonjosé: If $M\prec V_{\omega_1}$, then $V_{\omega+1}\in M$, but $M$ is countable, so $V_{\omega+1}$ is not a subset of $M$. When you collapse $M$ to be transitive, there is some $x\in M$ such that $M$ 'thinks' that $x$ is $V_{\omega+1}$, but that $x$ is not, itself, $V_{\omega+1}$.
Mar 4, 2022 at 12:08 comment added Ândson josé @AsafKaragila the sentences absolute over transitive models are $\Delta_{1}$, but be uncountable is $\Pi_{1}$, so i din't understand your point
Mar 4, 2022 at 12:03 comment added Ândson josé I don't think that is the heart of problem
Mar 4, 2022 at 6:23 comment added Asaf Karagila And in this case, any elementary submodel will contain many $V_\alpha$s which are uncountable, which witness its intransitivity.
Mar 4, 2022 at 1:25 history answered Noah Schweber CC BY-SA 4.0