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Feb 28, 2022 at 4:39 vote accept Ian Gershon Teixeira
Feb 24, 2022 at 4:50 comment added Ian Gershon Teixeira Ya I was thinking along the lines of intuition. And I really appreciate that! I just updated the question and I made sure to acknowledge your answer and say why I changed the question.
Feb 24, 2022 at 4:24 comment added LSpice @IanGershonTeixeira, in terms of changing the question, I think the usual etiquette after an answer has been given is to ask a new question. However, no, I do not mind, as long as you clearly indicate that the question was changed after this answer was given.
Feb 24, 2022 at 4:23 comment added LSpice @IanGershonTeixeira, I'm not sure I understand your argument. It is certainly possible for a connected group to intersect multiple components of a disconnected group, so I don't think your argument is yet a proof. Or were you just discussing an intuition?
Feb 24, 2022 at 4:23 comment added Ian Gershon Teixeira Do you mind if I slightly change the question to perhaps make it a bit closer to what I'm really interested in?
Feb 24, 2022 at 4:21 comment added Ian Gershon Teixeira ya another more geometric way to see it is that you are basically splitting up $ S_4 $ between the two connected components of an $ O_4 $ inside $ SL_5 $ ( $ A_4 $ in $ SO_4 $ and the 12 odd parity elements of $ S_4 $ in the other component of $ O_4 $). So it is not possible for any connected group to contain such a copy of $ S_4 $ since it would intersect both connected components of $ O_4 $ nontrivially contradicting connectedness. In particular $ SO_3 $ is connected so it cannot contain your $ S_4 $ subgroup.
Feb 24, 2022 at 4:03 history undeleted LSpice
Feb 24, 2022 at 4:00 history deleted LSpice via Vote
Feb 24, 2022 at 3:59 history undeleted LSpice
Feb 24, 2022 at 3:59 history edited LSpice CC BY-SA 4.0
Work with complex representations
Feb 24, 2022 at 3:17 history deleted LSpice via Vote
Feb 24, 2022 at 3:17 history answered LSpice CC BY-SA 4.0