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Timeline for Are countable models constructible?

Current License: CC BY-SA 4.0

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Feb 26, 2022 at 1:56 vote accept Frode Alfson Bjørdal
Feb 25, 2022 at 16:49 comment added Frode Alfson Bjørdal Ah, yes of course! :) What if (as is my real interest) S is ZFC minus the power set axiom, plus, for a countable ordinal $\gamma$, less than $\gamma$ applications of the power set operation?
Feb 24, 2022 at 16:32 comment added Andreas Blass Yes, $V\neq L$ is an axiom not in ZFC. But (1) is only part of ZFC. So the combination is not an extension of ZFC.
Feb 24, 2022 at 15:37 comment added Frode Alfson Bjørdal I don't understand. Doesn't (2) invoke an extra axiom? –
Feb 24, 2022 at 15:02 comment added Andreas Blass @FAB The $S$ in the first paragraph of my answer does not extend ZFC.
Feb 24, 2022 at 14:54 comment added Frode Alfson Bjørdal What about any first order S which does not extend ZFC? Will such an S have a model $L_\alpha$ for countable $\alpha$ if it has a countable model?
Feb 24, 2022 at 1:22 history answered Andreas Blass CC BY-SA 4.0