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Feb 22, 2022 at 7:02 vote accept CommunityBot
Feb 22, 2022 at 1:16 answer added R. van Dobben de Bruyn timeline score: 1
Feb 21, 2022 at 18:42 comment added user39380 @R.vanDobbendeBruyn Yes, thanks!
Feb 21, 2022 at 14:23 history edited user39380 CC BY-SA 4.0
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Feb 21, 2022 at 13:57 history edited LSpice CC BY-SA 4.0
lefschetz -> Lefschetz; PDF -> abs; link to Libgober article
Feb 21, 2022 at 13:55 history edited user39380 CC BY-SA 4.0
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Feb 21, 2022 at 13:48 history edited user39380 CC BY-SA 4.0
added 12 characters in body
Feb 21, 2022 at 13:39 history edited user39380 CC BY-SA 4.0
added 12 characters in body
Feb 21, 2022 at 12:44 comment added R. van Dobben de Bruyn Do you mean $H^{2n}$ instead of $H^n$ (or $\dim X = n+1$ instead of $2n+1$)? Because in the stated case, you get an isomorphism.
Feb 21, 2022 at 11:43 history asked user39380 CC BY-SA 4.0