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Jul 20, 2022 at 14:28 comment added Fedor Pakhomov @C7X I used confusing notations denoting as $\cong$ the elementary equivalence relation. I changed the notation to the more conventional $\equiv$.
Jul 20, 2022 at 14:27 history edited Fedor Pakhomov CC BY-SA 4.0
changed notation from \cong to \equiv
Jul 19, 2022 at 7:12 comment added C7X How do we have $(L_{\gamma};\in,\alpha)$ isomorphic to $(L_{\omega_1+n};\in,\omega_1)$ when the former's domain is countable and the latter's is uncountable?
Feb 23, 2022 at 17:14 comment added Fedor Pakhomov @Reflecting_Ordinal Sorry, indeed I haven't read your question careful enough. I have made the changes to the argument to incorporate the constants.
Feb 23, 2022 at 17:13 history edited Fedor Pakhomov CC BY-SA 4.0
Originally I misunderstood the question. Here I corrected the answer to address the question that was actually asked.
Feb 19, 2022 at 23:24 comment added Reflecting_Ordinal Why do this relation symbol is equivalent to the infinitely many constant symbol in condition?
Feb 19, 2022 at 15:50 history answered Fedor Pakhomov CC BY-SA 4.0