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Feb 19, 2022 at 15:49 vote accept ABB
Feb 19, 2022 at 15:47 comment added ABB @ Tim Campion, The reference is so helpful. Thanks a lot.
Feb 19, 2022 at 15:20 comment added Tim Campion For another description of the norm derived only from the $\ast$-algebra structure, see here. In fact, the "pre-norm" coming from the $\ast$-algebra structure in this sense is quite robust -- it fails to be a submultiplicative seminorm on a general $\ast$-algebra only in that it can take the value $\infty$.
Feb 19, 2022 at 15:19 history edited Simon Henry CC BY-SA 4.0
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Feb 19, 2022 at 14:59 history answered Simon Henry CC BY-SA 4.0