Timeline for Computing $\int^{4b}_0 {e^{-tx}\biggl(\frac{\sqrt{4bx-x^2}}{(2b-2c)^2+4cx}\biggr) dx}$
Current License: CC BY-SA 4.0
7 events
| when toggle format | what | by | license | comment | |
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| Feb 17, 2022 at 20:40 | review | Close votes | |||
| Mar 4, 2022 at 3:09 | |||||
| Feb 17, 2022 at 20:18 | comment | added | Carlo Beenakker | for $c=b$ your integral evaluates to $\frac{1}{2} \pi e^{-2 b t} [I_0(2 b t)+I_1(2 b t)]$ --- for $c\neq b$ a closed-form solution is not likely to be forthcoming. | |
| Feb 17, 2022 at 20:17 | history | edited | LSpice | CC BY-SA 4.0 |
Don't editorialise about the difficulty
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| Feb 17, 2022 at 20:07 | comment | added | Noam D. Elkies | It might help to know what was the function whose inverse Laplace transform you started with. | |
| Feb 17, 2022 at 19:49 | history | edited | Michael Hardy | CC BY-SA 4.0 |
added 5 characters in body
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| S Feb 17, 2022 at 19:40 | review | First questions | |||
| Feb 17, 2022 at 20:22 | |||||
| S Feb 17, 2022 at 19:40 | history | asked | Eduardo | CC BY-SA 4.0 |