EDIT:

Trying with the authors co-efficients, I managed to get:

m1 = ss;
m2 = (\[Delta] vs )/(((1 - l) (\[Mu] + \[Delta]) + \[Delta] l));
m3 = (\[Delta] ls )/(((1 - l) (\[Mu] + \[Delta]) + \[Delta] l));
m4 = ((\[Mu] + \[Delta]) is )/(((1 - 
         l) (\[Mu] + \[Delta]) + \[Delta] l));
m5 = (1/(\[Mu] + \[Rho])) (\[Rho]1 \[Beta] ss ts + \[Rho]1 \[Rho]2 \
\[Beta] ((\[Delta] vs ts)/((1 - 
             l) (\[Mu] + \[Delta]) + \[Delta] l)) + ((\[Rho] \[Delta] \
ts)/((1 - l) (\[Mu] + \[Delta]) + \[Delta] l)));

$xu$ term:

FullSimplify[-m1 \[Beta] is + m3 l \[Beta] ss is /ls + 
  m4 (1 - l) \[Beta] ss]

(* 0 *)

$xv$ term:

FullSimplify[-m1 \[Rho]1 \[Beta] ts + m3 \[Rho]1 l \[Beta] ss ts/ls + 
  m4 (1 - l) \[Beta] \[Rho]1 ss ts/is]

(* 0 *)

$z$ term:

FullSimplify[-(\[Mu] + \[Delta]) m3 + m4  \[Delta] ls/is]

(* 0 *)

$u$ term:

    FullSimplify[
     m1 \[Beta] is + m2 \[Rho]2 \[Beta] is - 
      m4 (\[Mu] + \[Alpha] + \[Gamma]) + m5 (\[Mu] + \[Rho])]

(* (-is \[Alpha] (\[Delta] + \[Mu]) - 
 is (\[Gamma] + \[Mu]) (\[Delta] + \[Mu]) + 
 is ss \[Beta] (\[Delta] + \[Mu] - l \[Mu]) - (-1 + 
    l) ss ts \[Beta] \[Mu] \[Rho]1 + is vs \[Beta] \[Delta] \[Rho]2 + 
 ts \[Delta] (\[Rho] + \[Beta] \[Rho]1 (ss + 
       vs \[Rho]2)))/(\[Delta] + \[Mu] - l \[Mu]) *)

$v$ term:

FullSimplify[
 m1 \[Rho]1 \[Beta] ts + \[Rho]2 \[Beta] \[Rho]1 ts m2 + 
  m3 \[Rho] ts/ls - m5 (\[Mu] + \[Rho])]

(* 0 *)

$yu$ term:

FullSimplify[m3 \[Rho]2 \[Beta] vs is/ls - \[Rho]2 \[Beta] is m2]

 (* 0 *)

$yv$ term:

FullSimplify[
 m3 \[Rho]2 \[Rho]1 \[Beta] vs ts/ls - \[Rho]2 \[Rho]1 \[Beta] ts m2]

 (* 0 *)

The $u$ term is causing some problems here, why?

Consider the following paper:

https://reader.elsevier.com/reader/sd/pii/S0893965917301611?token=4D46CE0CD4DEC9D9B6A988B5C5EBD28E17BA830CC4004D7262A209F791CC7AC11BA4C3183E572636E3A9E8113FBB17EB&originRegion=eu-west-1&originCreation=20220214125151

The methodology is understood in this paper apart from some technical things; How did the author arrive at constants $m_i, i=1,...,5$? They achieved this by killing the variable terms($xu, xv, z, u, v, yu, yv$), however when I try solving the system, it outputs all $m_i$'s equalling zero. Can someone show a detailed answer how they arrived at these constants and how they got their final form of the Lyapunov function(page 168)?

Code:

sol = Solve[{-m1 \[Beta] is + m3 l \[Beta] ss is/ls + 
     m4 (1 - l) \[Beta] ss == 
    0, -m1 \[Rho]1 \[Beta] ts + m3 \[Rho]1 l \[Beta] ss ts/ls + 
     m4 (1 - l) \[Beta] \[Rho]1 ss ts/is == 
    0, -(\[Mu] + \[Delta]) m3 + m4 \[Delta] ls/is == 0, 
   m1 \[Beta] is + m2 \[Rho]2 \[Beta] is - 
     m4 (\[Mu] + \[Alpha] + \[Gamma]) + m5 (\[Mu] + \[Rho]) == 0, 
   m1 \[Rho]1 \[Beta] ts + m2 \[Rho]1 \[Rho]2 \[Beta] ts + 
     m3 \[Rho] ts/ls - m5 (\[Mu] + \[Rho]) == 
    0, -m2 \[Rho]2 \[Beta] is + m3 \[Rho]2 \[Beta] vs is/ls == 
    0, -m2 \[Rho]1 \[Rho]2 \[Beta] ts + 
     m3 \[Rho]1 \[Rho]2 \[Beta] vs ts/ls == 0 }, {m1, m2, m3, m4, m5}]

Consider the following paper:

"A note on global stability for a tuberculosis model" by Gao and Huang: https://doi.org/10.1016/j.aml.2017.05.004

The methodology is understood in this paper apart from some technical things; How did the author arrive at constants $m_i, i=1,...,5$? They achieved this by killing the variable terms  ($xu, xv, z, u, v, yu, yv$), however when I try solving the system, it outputs all $m_i$'s equalling zero. Can someone show a detailed answer how they arrived at these constants and how they got their final form of the Lyapunov function  (page 168)?

Code:

sol = Solve[{-m1 \[Beta] is + m3 l \[Beta] ss is/ls + 
     m4 (1 - l) \[Beta] ss == 
    0, -m1 \[Rho]1 \[Beta] ts + m3 \[Rho]1 l \[Beta] ss ts/ls + 
     m4 (1 - l) \[Beta] \[Rho]1 ss ts/is == 
    0, -(\[Mu] + \[Delta]) m3 + m4 \[Delta] ls/is == 0, 
   m1 \[Beta] is + m2 \[Rho]2 \[Beta] is - 
     m4 (\[Mu] + \[Alpha] + \[Gamma]) + m5 (\[Mu] + \[Rho]) == 0, 
   m1 \[Rho]1 \[Beta] ts + m2 \[Rho]1 \[Rho]2 \[Beta] ts + 
     m3 \[Rho] ts/ls - m5 (\[Mu] + \[Rho]) == 
    0, -m2 \[Rho]2 \[Beta] is + m3 \[Rho]2 \[Beta] vs is/ls == 
    0, -m2 \[Rho]1 \[Rho]2 \[Beta] ts + 
     m3 \[Rho]1 \[Rho]2 \[Beta] vs ts/ls == 0 }, {m1, m2, m3, m4, m5}]