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Feb 13, 2022 at 20:58 vote accept Student
Feb 13, 2022 at 20:18 answer added Iosif Pinelis timeline score: 3
Feb 13, 2022 at 16:15 comment added username So $(rv^\prime)^2+(1-m/2)v^2=o(r^{2-m})$ and $v^q=o(r^{-m})$ therefore when $m\geq2$, the constant must be zero. And then you solve it by the usual way "v" on one side, "r" on the other?
Feb 13, 2022 at 16:01 history edited Daniele Tampieri CC BY-SA 4.0
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Feb 13, 2022 at 11:39 history edited YCor CC BY-SA 4.0
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Feb 13, 2022 at 10:05 history asked Student CC BY-SA 4.0