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Feb 13, 2022 at 20:47 comment added Chase Roberts Oh no! I was afraid this was the case. Your proof is very elegant so I can’t even argue with it. My only criticism is that my question was about minimizing not maximizing, but your general proof would still work in the minimizing case if you set $A$ equal to 1 - (n adjacency matrix) instead
Feb 13, 2022 at 20:44 vote accept Chase Roberts
Feb 13, 2022 at 9:55 history edited LeechLattice CC BY-SA 4.0
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Feb 13, 2022 at 9:49 history answered LeechLattice CC BY-SA 4.0