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Feb 16, 2022 at 13:18 history edited Salvo Tringali CC BY-SA 4.0
fixed minor details
Feb 14, 2022 at 9:53 history edited Salvo Tringali CC BY-SA 4.0
rewritten in the light of the OP's clarifications
Feb 14, 2022 at 9:48 history edited Salvo Tringali CC BY-SA 4.0
rewritten in the light of the OP's clarifications
Feb 13, 2022 at 23:13 comment added Salvo Tringali Exactly! If you don't want to keep track of the additive structure of $\mathbb N$, then the multiplicative structure of $\mathbb N^+$ is no different than that of a free ab. monoid on a countably infinite set. If, on the other hand, you do want to keep track of the additive structure of $\mathbb N$, then it's a totally different story and I think this should be made clear in the OP (maybe by saying that you're looking for a semiring embedding $f:\mathbb N \to S$ s.t. $f(p)$ has an essentially unique and non-trivial factorization into "indecomposable elements" of $S$ for each prime $p$).
Feb 13, 2022 at 22:31 comment added Zelox Yes, your claim is right, and I did not deny it. I may not make my point clear. If the additive structure of $\mathbb N^+$ is forgotten and we only consider its multiplication, then it should not be called "natural number" anymore. $\mathbb N^+$ becomes a free monoid generated by a countable set $\mathbb P$, but now $\mathbb P$ is merely a countable set.
Feb 13, 2022 at 19:10 comment added Salvo Tringali By Theorem 1.2.9 in Geroldinger & Halter-Koch's book (see my answer), a commutative and cancellative monoid is a unique factorization monoid iff it is a free abelian monoid modulo units: This applies, in particular, to the multiplicative monoid of the non-zero elements of a commutative semidomain $S$ with the unique factorization property and has nothing to do with the additive structure of $S$.
Feb 13, 2022 at 16:22 comment added Zelox Also, you may interpret condition (3) any way you like as long as all primes can be described in an unified manner, like $-1$ is viewed as $i^2$ in complex number.
Feb 13, 2022 at 16:11 comment added Zelox However, embedding $\mathbb N^+$ to $\mathscr F_{\rm ab}(X)$, instead of $X$, may yield interesting results, as mentioned at the third part of the post. But the difficulty is how we embed $\mathbb N^+$.
Feb 13, 2022 at 16:11 comment added Zelox As you may get from my motivation that my intention is to find an extension of $\mathbb N^+$ in which primes can be further factored such that we may focus on studying elements more fundamental than primes. In this regard, embedding $\mathbb N^+$ to a set $X$ then form the free abelian monoid $\mathscr F_{\rm ab}(X)$ doesn't make things easier, but more complicated; the primes are still primes and we get more elements that are formal product of natural numbers which is not intended.
Feb 13, 2022 at 16:10 comment added Zelox Thank you for point out the factorization Theory. It is certainly useful in some respect. The target algebraic system is indeed a commutative monoid if we forget the addition of natural numbers. However, not considering the extension of addition does not mean that the addition of $\mathbb N^+$ should be forgotten; since otherwise its arithmetic properties are erased. I might be unclear on this and I'm sorry for causing confusions.
Feb 13, 2022 at 10:38 history edited Salvo Tringali CC BY-SA 4.0
fixed an annoying detail (on whether 0 is or not a natural number)
Feb 12, 2022 at 22:50 history edited Salvo Tringali CC BY-SA 4.0
reorganized the post to make it hopefully more readable and fixed a couple more of mistakes
Feb 12, 2022 at 21:37 history edited Salvo Tringali CC BY-SA 4.0
fixed a couple of details
Feb 12, 2022 at 21:08 history edited Salvo Tringali CC BY-SA 4.0
added the definition of atom
Feb 12, 2022 at 20:49 history answered Salvo Tringali CC BY-SA 4.0