Timeline for The exploration of the asymptotic behavior of a simple sum. $\sum_{k=1}^{\infty} (k^{1/k} - 1)$ [closed]
Current License: CC BY-SA 4.0
26 events
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| Feb 10, 2022 at 22:44 | comment | added | FusRoDah | Btw, if you want the asymptotic behaviour of $\sum_{k\leq x} k^{1/k} - 1$ for $x$ large, it seems to be given by $\frac 1 2 \ln^2 x + C + \frac {\ln x} {2x} + \cdots$. | |
| Feb 10, 2022 at 21:48 | history | closed |
Stopple Peter Humphries Lucia GH from MO LSpice |
Needs details or clarity | |
| Feb 10, 2022 at 20:37 | comment | added | user475930 | I don't really have questions. I've wandered into the wrong house. | |
| Feb 10, 2022 at 20:36 | history | edited | user475930 | CC BY-SA 4.0 |
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| Feb 9, 2022 at 22:37 | history | edited | user475930 | CC BY-SA 4.0 |
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| Feb 9, 2022 at 21:57 | vote | accept | CommunityBot | ||
| Feb 9, 2022 at 20:49 | comment | added | François Brunault | @TheHoyt What are your other questions exactly? You could summarize them at the bottom of your post for example. | |
| Feb 9, 2022 at 20:34 | comment | added | GH from MO | Well, saying "What a waste of time" is not helpful. Other than that: take it easy! | |
| Feb 9, 2022 at 20:33 | history | edited | user475930 | CC BY-SA 4.0 |
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| Feb 9, 2022 at 20:30 | comment | added | user475930 | To abide by that format, I would essentially have the first 3 lines, then answer my own question with the rest. Is it too late now? What should I do. | |
| Feb 9, 2022 at 20:25 | comment | added | GH from MO | It is standard policy at MathOverflow to restrict to one question per post. Otherwise someone answers one of the included questions, but the proposer will not be satisfied, because the other questions are left unanswered. Multiple questions and long posts are a source of frustration. And yes, this site indeed is about answering questions. | |
| Feb 9, 2022 at 20:19 | history | edited | user475930 | CC BY-SA 4.0 |
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| Feb 9, 2022 at 20:08 | comment | added | user475930 | It was phrased as if it was a lesson and this site hyper focuses on answering a question. | |
| Feb 9, 2022 at 20:07 | history | edited | user475930 | CC BY-SA 4.0 |
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| Feb 9, 2022 at 20:00 | comment | added | GH from MO | Please restrict to one question per post. Also, you probably meant $\sum (k^{1/k}-1)$ instead of $\sum k^{1/k}-1$. | |
| Feb 9, 2022 at 19:58 | history | edited | user475930 | CC BY-SA 4.0 |
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| Feb 9, 2022 at 19:18 | history | edited | user475930 | CC BY-SA 4.0 |
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| Feb 9, 2022 at 19:10 | history | edited | user475930 | CC BY-SA 4.0 |
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| Feb 9, 2022 at 18:58 | answer | added | Carlo Beenakker | timeline score: 10 | |
| Feb 9, 2022 at 18:56 | review | Close votes | |||
| Feb 10, 2022 at 21:51 | |||||
| Feb 9, 2022 at 18:47 | history | edited | Michael Hardy | CC BY-SA 4.0 |
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| Feb 9, 2022 at 18:44 | history | edited | user475930 | CC BY-SA 4.0 |
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| Feb 9, 2022 at 18:37 | history | undeleted | user475930 | ||
| Feb 9, 2022 at 18:36 | history | deleted | user475930 | via Vote | |
| Feb 9, 2022 at 18:30 | history | edited | user475930 | CC BY-SA 4.0 |
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| Feb 9, 2022 at 18:25 | history | asked | user475930 | CC BY-SA 4.0 |