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Feb 10, 2022 at 4:29 comment added Math The Novice Thank you for your kind answer, but in this example $z = \frac{1}{2}\sqrt{1+z}$ can be reformulated as $4z^2 = z + 1$ (to remove the singularity of $\sqrt{\cdot}$), which can be solved by Newton's method (Banach fixed point method). I wonder if any problem has a Banach method solution behind (if properly reformulated) or the regularity assumptions of the problem will prevent Banach method to be implemented.
Feb 9, 2022 at 20:19 history edited Daniele Tampieri CC BY-SA 4.0
Minor grammar improvements and removal of unnecessary data from references
Feb 9, 2022 at 17:59 history answered Daniele Tampieri CC BY-SA 4.0