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Feb 7, 2022 at 19:46 vote accept Ya He
Feb 7, 2022 at 16:59 comment added Ya He @MoisheKohan Very sorry, it's my first time to use the two websites. I have deleted the similar post on StackExchange. Thank you.
Feb 7, 2022 at 1:15 comment added Moishe Kohan Cross-posted here.
Feb 6, 2022 at 21:34 comment added Ya He @BenMcKay Thanks for the clarification. The motivation of my question is that: simplices and cubes frequently occur in economic theory such as general equilibrium and Nash equilibrium. Those economics papers apply PH index theorem (as shown in the above picture) to manifolds with corners (e.g., simplices and cubes).
Feb 6, 2022 at 18:29 history became hot network question
Feb 6, 2022 at 16:04 history edited LSpice CC BY-SA 4.0
Poincare -> Poincaré; link to book
Feb 6, 2022 at 14:42 comment added Ben McKay @YaHe: the simplex is a manifold with corners. In particular, the simplex you have written down is an equilateral triangle. Note that angles at corners less than 180 can be altered by change of variables, to any other angle less than 180.
Feb 6, 2022 at 14:35 answer added mlk timeline score: 11
Feb 6, 2022 at 13:56 history edited Ya He CC BY-SA 4.0
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Feb 6, 2022 at 13:31 comment added mlk @LoïcTeyssier I think quarter-singularity might be a misleading term here. Corners need not be right angle, so any number of them could join up to form a full singularity. But I guess the definition of degree as signed relative area of $S^{n-1}$ covered by the map would work safely for any angle.
Feb 6, 2022 at 12:26 comment added Ya He @LoïcTeyssier Thanks for your comments. I have a question: Is the simplex (e.g., $S = \{ ({x_1},{x_2},{x_3}):\sum\limits_{i = 1}^3 {{x_i}} = 1,{\rm{ }}{x_i} \ge 0\}$) a manifold with corners? It has three angles.
Feb 6, 2022 at 12:09 comment added Loïc Teyssier The obvious thing that discriminates both situations from the point of view of vector fields is whether or not a singularity sits in a corner. Then, you'll have to define what is the index of these "quarter"-singularities (which is OK if the boundary of the manifold is assumed invariant by the vector field).
Feb 6, 2022 at 12:07 comment added Loïc Teyssier If what you seek exists, you should consider an object that encodes the $C^1$-difference between a closed disc and a closed square: at the topological level both objects coincide. Probably the number of corner / the collection of their angles is relevant.
S Feb 6, 2022 at 10:26 review First questions
Feb 6, 2022 at 12:13
S Feb 6, 2022 at 10:26 history asked Ya He CC BY-SA 4.0