Let $\textbf{Top}$ be the category of all topological spaces. I mean to include the bad ones – topological spaces not locally contractible, topological spaces not having the homotopy type of a CW-complex, non-discrete totally disconnected spaces, non-$T_0$ spaces, you name it. As is well known, $\textbf{Top}$ is not cartesian closed, but this is no obstruction to getting a decentvery good simplicial enrichment:
Given topological spaces $X$ and $Y$, we have a natural simplicial set $\textrm{Map} (X, Y)$ where the $n$-simplices are the continuous maps $X \times \left| \Delta^n \right| \to Y$. From this definition it is immediate that $\textrm{Map} (X, -) : \textbf{Top} \to \textbf{sSet}$ preserves limits and therefore has a left adjoint, which I write as $X \odot {-} : \textbf{sSet} \to \textbf{Top}$.
Since $\left| \Delta^n \right|$ is compact Hausdorff, it is exponentiable a fortiori, so $\textrm{Map} (X, Y)_n$ is equivalently the set of continuous maps $X \to Y^{\left| \Delta^n \right|}$. Hence $\textrm{Map} (-, Y) : \textbf{Top}^\textrm{op} \to \textbf{sSet}$ also preserves limits and has a left adjoint, which I write as ${-} \pitchfork Y : \textbf{sSet} \to \textbf{Top}^\textrm{op}$.
(This probably surprises some people, since $\left| K \right|$ is not necessarily exponentiable for an infinite simplicial set $K$. The short answer is that $X \odot K$ is not necessarily the same as $X \times \left| K \right|$, and $K \pitchfork Y$ is not necessarily the same as $Y^{\left| K \right|}$. Rather, $X \odot K = \int^n X \times \left| \Delta^n \right| \times K_n$ and $K \pitchfork Y = \int_n Y^{\left| \Delta^n \right| \times K_n}$. When $X$ (!!) is exponentiable then $X \odot K \cong X \times \left| K \right|$.)
There is an evident simplicial composition map $\textrm{Map} (Y, Z) \times \textrm{Map} (X, Y) \to \textrm{Map} (X, Z)$: given $g : Y \times \left| \Delta^n \right| \to Z$ and $f : X \times \left| \Delta^n \right| \to Y$, define $g \circ_n f$ to be the composite $$\require{AMScd} \begin{CD} X \times \left| \Delta^n \right| @>{\textrm{id}_X \times \delta_{\left| \Delta^n \right|}}>> X \times \left| \Delta^n \right| \times \left| \Delta^n \right| @>{f \times \textrm{id}_{\left| \Delta^n \right|}}>> Y \times \left| \Delta^n \right| @>{g}>> Z \end{CD}$$ where $\delta_{\left| \Delta^n \right|} : \left| \Delta^n \right| \to \left| \Delta^n \right| \times \left| \Delta^n \right|$ is the diagonal embedding.
(Basically we are exploiting the fact that every object – so $\left| \Delta^n \right|$ in particular – in a cartesian monoidal category has a unique comonoid structure. You can do this kind of thing whenever you have a comonoid in a monoidal category.)
We get an $\textbf{sSet}$-enrichment of $\textbf{Top}$, but unfortunately it is not clear whether it it tensored and cotensored. I have seen it claimedconvinced myself that we have tensors and cotensors for finite simplicial sets, but thereit is some point-set topology involved in checking this. I think finite tensorstensored and cotensors suffice, at any ratecotensored (but watch this other question).
(If we restrict to a complete and cocomplete cartesian closed subcategory of $\textbf{Top}$ containing the standard simplices and their finitary products, then there is definitely no problem, and the subtlety about $\odot$ and $\pitchfork$ also goes away.)
In fact, $\textrm{Map} (X, Y)$ is a Kan complex for all $X$ and $Y$: indeed, the natural map $$\textrm{Hom}_\textbf{sSet} (\Delta^n, \textrm{Map} (X, Y)) \to \textrm{Hom}_\textbf{sSet} (\Lambda^n_k, \textrm{Map} (X, Y))$$ is a split surjection, because it can be naturally identified with the natural map $$\textrm{Hom}_\textbf{Top} (X, Y^{\left| \Delta^n \right|}) \to \textrm{Hom}_\textbf{Top} (X, Y^{\left| \Lambda^n_k \right|})$$ induced by the inclusion $\left| \Lambda^n_k \right| \to \left| \Delta^n \right|$, which has a (non-canonical) retraction.