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S Feb 5, 2022 at 3:26 history suggested Buzz CC BY-SA 4.0
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Feb 4, 2022 at 20:36 review Suggested edits
S Feb 5, 2022 at 3:26
Feb 4, 2022 at 13:10 history edited Bertrand CC BY-SA 4.0
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Feb 4, 2022 at 12:49 comment added Bertrand Yes, you are right, in the sense of distribution, there is a Mellin transform for $X^{\alpha}$. I am not very familiar with distribution and considered only basic definition of Mellin transform. Indeed, considering your remark we can conclude, I will modify my answer.
Feb 3, 2022 at 22:02 comment added Steven Clark I'm not sure I understand your answer as $\mathcal{M}_t\left[t^a\right](s)=2 \pi \delta (i (a+s))$ (see wolframalpha.com/input?i=MellinTransform%5Bt%5Ea%2C+t%2C+s%5D). For a derivation of this result see the last part of the answer I posted at mathoverflow.net/q/294849.
Feb 3, 2022 at 13:21 history edited Bertrand CC BY-SA 4.0
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Feb 3, 2022 at 13:03 history answered Bertrand CC BY-SA 4.0