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Feb 3, 2022 at 13:26 vote accept Sam Hopkins
Jan 31, 2022 at 22:28 history became hot network question
Jan 31, 2022 at 17:56 answer added Sam Hopkins timeline score: 8
Jan 31, 2022 at 17:18 comment added Sam Hopkins @Nate: I'm trying to understand your comment. Let $G=\langle (1,2,3,4) \rangle$ act on $X = \{1,2,3,4\}$ in the usual way. Then the polynomial is $\frac{1}{4}(k^4+k^2+2k)=6 \binom{k}{4} + 9\binom{k}{3} + 4 \binom{k}{2} + \binom{k}{1}$. But there are not $6$ equivalence relations with $4$ classes on $X$, right? Maybe you intend "labeled equivalence relations"?
Jan 31, 2022 at 15:59 comment added Nate I think $a_j$ is the number of equivalence relations with exactly $j$ classes on $X$, up to the action of $G$.
Jan 31, 2022 at 14:25 history asked Sam Hopkins CC BY-SA 4.0