Timeline for Sturm-Liouville result
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
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| Feb 2, 2022 at 17:25 | comment | added | Math604 | I was convinced there was no simple little formula but I made a mistake. After looking for solutions of the form $ \psi(\theta)= A - \cos(4 \theta)$ I believe there is a simple solution. So I guess I should close the question. Thanks for all the comments. | |
| Jan 30, 2022 at 20:30 | history | edited | Math604 | CC BY-SA 4.0 |
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| Jan 30, 2022 at 20:03 | history | edited | Math604 | CC BY-SA 4.0 |
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| Jan 30, 2022 at 19:00 | comment | added | Christian Remling | So normally one would insist that $\omega > 0$ ... | |
| Jan 30, 2022 at 18:59 | comment | added | Christian Remling | @PierrePC: Yes, that would be the standard operator associated with this SL equation. It acts on $L^2(\omega\, dx)$. | |
| Jan 30, 2022 at 18:04 | history | edited | Math604 | CC BY-SA 4.0 |
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| Jan 30, 2022 at 18:02 | comment | added | Math604 | I knew I wrote a sloppy question but I didn't realize it was this bad. Let me go edit it a bit. | |
| Jan 30, 2022 at 10:17 | comment | added | Pierre PC | Maybe it's obvious for the other viewers but it isn't for me: what is your operator? Is it $\psi\mapsto-(\omega\psi')'/\omega$? Or does it act on $\omega$? Is $n$ the dimension? What is $\omega$, a smooth function? You're asking for the eigenvalue of an equality, is $\mu_1$ a notation for your eigenvalue? For me, your question is very difficult to read, and requires a few more precisely stated “Let ... be ...”. | |
| Jan 30, 2022 at 0:05 | history | asked | Math604 | CC BY-SA 4.0 |