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Jan 31, 2022 at 16:14 vote accept Gabriel
Jan 31, 2022 at 14:53 answer added Uriya First timeline score: 2
Jan 31, 2022 at 14:53 comment added Uriya First @Gabriel Very well.
Jan 30, 2022 at 8:52 comment added Gabriel @UriyaFirst This solves my question. Thank you. If you would like to turn this into an answer, I'll gladly accept it.
Jan 29, 2022 at 20:09 comment added Uriya First You can define the reduced norm using fpqc descent. Have a look at chapter III, section 1.2 in Knus' "Quadratic and Hermitian Forms over Rings", for instance.
Jan 29, 2022 at 16:48 comment added Gabriel @PiotrAchinger precisely! The finiteness is very simple (an isomorphism $A_{\bar{k})\cong M_n(\bar{k})$ involves only a finite amount of data, so we can find a finite extension which does the job). The hard part is proving the existence of a separable splitting field.
Jan 29, 2022 at 16:41 comment added Piotr Achinger @მამუკაჯიბლაძე The way I understood the question, it's about the difference between separable and algebraic closure, not about finiteness of the splitting field extension.
Jan 29, 2022 at 13:59 comment added მამუკა ჯიბლაძე A finite index subgroup of $\operatorname{Gal}(\bar k/k)$ fixes $A_{\bar k}$, what else can be said?
Jan 29, 2022 at 13:39 history asked Gabriel CC BY-SA 4.0