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Jan 29, 2022 at 13:34 vote accept Andi Bauer
Jan 29, 2022 at 3:48 history became hot network question
Jan 28, 2022 at 20:50 answer added John Rognes timeline score: 16
Jan 28, 2022 at 20:46 comment added Will Sawin We can make $K(G,i)$ by gluing to a point one $i$-cell for each generator of $G$, then one $i+1$-cell for each relation, and then additional cells to kill the remaining homotopy groups. The remaining homotopy groups are in degree $i+1$ and above, so we kill them by adding cells of dimension $i+2$ and above, which can't add any new cohomology classes in degree $i+1$. Then the cells we added in degree $i+1$ for the relations must give the Bocksteins.
Jan 28, 2022 at 19:46 history asked Andi Bauer CC BY-SA 4.0