Timeline for Do we know anything about Harder-Narasimhan filtrations of tensor products of vector bundles?
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
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| Jan 27, 2022 at 14:23 | comment | added | diverietti | @Will Sawin, yes of course, I red too fast your answer, sorry! | |
| Jan 27, 2022 at 13:13 | comment | added | Will Sawin | @diverietti Yes, the Kobayashi-Hitchin correspondence generalizes the Narasimhan–Seshadri theorem (from which this follows) from curves to higher-dimensional varieties. | |
| Jan 27, 2022 at 13:11 | comment | added | Will Sawin | @user127776 I meant to say that both were semistable. (But the result would follow, since the tensor product would be an iterated extension of semistable bundles of the same slope.) | |
| Jan 27, 2022 at 13:10 | history | edited | Will Sawin | CC BY-SA 4.0 |
added 4 characters in body
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| Jan 27, 2022 at 11:18 | comment | added | Yikun Qiao | @user127776 I found a review for this result ems.press/content/serial-article-files/10191. May be helpful. | |
| Jan 27, 2022 at 11:03 | comment | added | diverietti | You can infer this from the Kobayashi-Hitchin correspondence | |
| Jan 27, 2022 at 10:03 | vote | accept | Yikun Qiao | ||
| Jan 27, 2022 at 4:35 | comment | added | user127776 | Your claim states that if one is stable and the other one is semistable the tensor is semistable. Now how do you deduce that tensor product of two semistable is semistable? | |
| Jan 27, 2022 at 3:52 | history | answered | Will Sawin | CC BY-SA 4.0 |