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Jan 25, 2022 at 20:44 vote accept Francesco Polizzi
Jan 25, 2022 at 20:42 comment added Francesco Polizzi Very clean explanation. Morally, since the fibres of a Kodaira fibrations have genus at least $2$ (actually, at least $3$) there is a moduli space $\mathcal{M}$ for them. If $y \in Y$, there is a germ of deformation $\mathcal{X} \to U$ of the fibre $X_y$, where $U$ is a small neighborhood of $y$ in $Y$. Then the KS map is the differential of the corresponding moduli map $U \to \mathcal{M}$, and composing with a base change of $U$ ramified at $y$ we obtain a map whose differential vanishes at $y$ (by the chain rule). Thank you for pointing this out to me.
Jan 25, 2022 at 20:10 history answered Nikolas Kuhn CC BY-SA 4.0