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May 4, 2022 at 18:22 history edited T. Amdeberhan CC BY-SA 4.0
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Jan 24, 2022 at 18:34 vote accept T. Amdeberhan
Jan 24, 2022 at 18:22 comment added Ira Gessel @TAmdeberhan Yes, if $q$ is not a prime then the number $a_q(n)$ as defined are not integers. The “right” analogue of Michael Somos's equation when $q$ is a power of the prime $p$ is $$A_q(x)^q = \frac{A(x^p)^{q/p}}{1-qxA(x^p)^{q/p}}.$$ (We also require that $A_q(0)=1$.) The coefficients of $A_q(x)$ defined this way are integers.
Jan 24, 2022 at 17:46 comment added T. Amdeberhan Thank you for the answer here. Hope to read the promised proofs in your upcoming paper, soon. On the other hand, do you agree that $a_q(n)$ need not be integers when $q$ is a power of a primes. I checked with $q=2^2$ and they reveal rational numbers.
Jan 24, 2022 at 5:02 history edited Ira Gessel CC BY-SA 4.0
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Jan 23, 2022 at 22:14 history edited Ira Gessel CC BY-SA 4.0
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Jan 23, 2022 at 19:16 history answered Ira Gessel CC BY-SA 4.0