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Jan 23, 2022 at 18:50 history edited user21820 CC BY-SA 4.0
edited tags; edited title
Jan 23, 2022 at 15:57 comment added Yinpo I mean 𝑒 is an example of an irritational number, the base of natural logarithms. Or generalized speaking, this could be random irrational number. Sorry for the ambiguity of my explanation.
Jan 23, 2022 at 11:35 history became hot network question
Jan 23, 2022 at 4:33 comment added Will Sawin @LSpice It does matter in that one wants $e$ to be an irrational number for the result to be applied - e.g. if $e=2$ there is a problem.
Jan 23, 2022 at 4:20 comment added LSpice I made an attempt to clarify the wording, but did not explicitly venture an assumption whether, as in @MichaelEngelhardt's comment, $\ln(e) = 1$. Hopefully @‍Yinpo will clarify, although @‍2734364041's answer suggests it doesn't matter.
Jan 23, 2022 at 4:19 history edited LSpice CC BY-SA 4.0
Wording
Jan 23, 2022 at 3:53 answer added 2734364041 timeline score: 25
Jan 23, 2022 at 3:48 comment added Michael Engelhardt Is $e$ meant to be the base of natural logarithms?
Jan 23, 2022 at 3:47 comment added CommunityBot Please clarify your specific problem or provide additional details to highlight exactly what you need. As it's currently written, it's hard to tell exactly what you're asking.
S Jan 23, 2022 at 3:29 review First questions
Jan 23, 2022 at 3:47
S Jan 23, 2022 at 3:29 history asked Yinpo CC BY-SA 4.0