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Feb 4, 2022 at 8:45 comment added Adrien MORIN Have you had a look at math.stackexchange.com/questions/3314133/… ?
Jan 19, 2022 at 17:46 comment added Piotr Achinger This is meant to be a tautology. If $df_p$ is an isomorphism, i.e. $f$ is etale at $p$, then there exists an open neighborhood $V$ of $p$ such that $f|_V$ is etale. This $V$ is then an etale neighborhood of $f(p)$, and so $f$ tautologically gives an isomorphism from $V$ (a neighborhood of $p$) to $V$ (a neighborhood of $f(p)$).
Jan 19, 2022 at 17:40 comment added Gabriel @DenisNardin Could you give more details about why this is trivial if we replace the source as well? I get that (1) is used for proving that $f$ is étale, but I don't see how to find the étale neighborhood of $p$.
Jan 19, 2022 at 17:32 comment added Denis Nardin The last statement you ask about is false even in the differentiable category (just take any non-trivial covering space). If you allow the source to be replaced by an étale neighborhood of $p$ as well, this makes the statement true and a trivial consequence of your property (1).
Jan 19, 2022 at 17:29 history asked Gabriel CC BY-SA 4.0