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Max Alekseyev
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Here is some computational evidence that $n\in\{1,2,4\}$ are the only $n$ that deliver an integer sum.

For an odd prime $p$, let $a_p < b_p$ denote two smallest even positive integers such that $a_pp+1$ and $b_pp+1$ are prime. Then $n\in \big[a_pp+1,\min\{b_pp+1,p^2\}\big)$ cannot deliver an integer sum as its denominator will necessarily contain $p$. Here are these intervals for primes $p<100$:

3 [7, 9)
5 [11, 25)
7 [29, 43)
11 [23, 67)
13 [53, 79)
17 [103, 137)
19 [191, 229)
23 [47, 139)
29 [59, 233)
31 [311, 373)
37 [149, 223)
41 [83, 739)
43 [173, 431)
47 [283, 659)
53 [107, 743)
59 [709, 827)
61 [367, 733)
67 [269, 1609)
71 [569, 853)
73 [293, 439)
79 [317, 1423)
83 [167, 499)
89 [179, 1069)
97 [389, 971)

As we can see primes 5, 11, 29, 41, 67 alone cover the interval $[11, 1609)$, while others provide extensive backup support. Such a pattern will likely continue to cover all integers above $11$. However I'm not sure whether this observation can be justified theoretically without relying on unproved conjectures.

ADDED. Primes 5, 11, 29, 41, 67, 743, 7823, 165293, 6215171 cover the interval $[11,1131161123)$.

Here is some computational evidence that $n\in\{1,2,4\}$ are the only $n$ that deliver an integer sum.

For an odd prime $p$, let $a_p < b_p$ denote two smallest even positive integers such that $a_pp+1$ and $b_pp+1$ are prime. Then $n\in \big[a_pp+1,\min\{b_pp+1,p^2\}\big)$ cannot deliver an integer sum as its denominator will necessarily contain $p$. Here are these intervals for primes $p<100$:

3 [7, 9)
5 [11, 25)
7 [29, 43)
11 [23, 67)
13 [53, 79)
17 [103, 137)
19 [191, 229)
23 [47, 139)
29 [59, 233)
31 [311, 373)
37 [149, 223)
41 [83, 739)
43 [173, 431)
47 [283, 659)
53 [107, 743)
59 [709, 827)
61 [367, 733)
67 [269, 1609)
71 [569, 853)
73 [293, 439)
79 [317, 1423)
83 [167, 499)
89 [179, 1069)
97 [389, 971)

As we can see primes 5, 11, 29, 41, 67 alone cover the interval $[11, 1609)$, while others provide extensive backup support. Such a pattern will likely continue to cover all integers above $11$. However I'm not sure whether this observation can be justified theoretically without relying on unproved conjectures.

Here is some computational evidence that $n\in\{1,2,4\}$ are the only $n$ that deliver an integer sum.

For an odd prime $p$, let $a_p < b_p$ denote two smallest even positive integers such that $a_pp+1$ and $b_pp+1$ are prime. Then $n\in \big[a_pp+1,\min\{b_pp+1,p^2\}\big)$ cannot deliver an integer sum as its denominator will necessarily contain $p$. Here are these intervals for primes $p<100$:

3 [7, 9)
5 [11, 25)
7 [29, 43)
11 [23, 67)
13 [53, 79)
17 [103, 137)
19 [191, 229)
23 [47, 139)
29 [59, 233)
31 [311, 373)
37 [149, 223)
41 [83, 739)
43 [173, 431)
47 [283, 659)
53 [107, 743)
59 [709, 827)
61 [367, 733)
67 [269, 1609)
71 [569, 853)
73 [293, 439)
79 [317, 1423)
83 [167, 499)
89 [179, 1069)
97 [389, 971)

As we can see primes 5, 11, 29, 41, 67 alone cover the interval $[11, 1609)$, while others provide extensive backup support. Such a pattern will likely continue to cover all integers above $11$. However I'm not sure whether this observation can be justified theoretically without relying on unproved conjectures.

ADDED. Primes 5, 11, 29, 41, 67, 743, 7823, 165293, 6215171 cover the interval $[11,1131161123)$.

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Max Alekseyev
  • 34.3k
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  • 152

Here is some computational evidence for finiteness of suchthat $n\in\{1,2,4\}$ are the only $n$ that deliver an integer sum. 

For an odd prime $p$, let $a_p < b_p$ denote two smallest even positive integers such that $a_pp+1$ and $b_pp+1$ are prime. Then $n\in [a_pp+1,\min(b_pp+1,p^2))$$n\in \big[a_pp+1,\min\{b_pp+1,p^2\}\big)$ cannot deliver an integer sum as its denominator containswill necessarily contain $p$. Here are these intervals for primes below $100$$p<100$:

3 [7, 9)
5 [11, 25)
7 [29, 43)
11 [23, 67)
13 [53, 79)
17 [103, 137)
19 [191, 229)
23 [47, 139)
29 [59, 233)
31 [311, 373)
37 [149, 223)
41 [83, 739)
43 [173, 431)
47 [283, 659)
53 [107, 743)
59 [709, 827)
61 [367, 733)
67 [269, 1609)
71 [569, 853)
73 [293, 439)
79 [317, 1423)
83 [167, 499)
89 [179, 1069)
97 [389, 971)

As we can see primes 5, 11, 29, 41, 67 alone cover the interval $[11, 1609)$, while others provide extensive backup support. Such a pattern will likely continue to cover all integers above $11$. However I'm not sure whether this observation can be justified theoretically without relying on unproved conjectures.

Here is some computational evidence for finiteness of such $n$. For an odd prime, let $a_p < b_p$ denote two smallest even positive integers such that $a_pp+1$ and $b_pp+1$ are prime. Then $n\in [a_pp+1,\min(b_pp+1,p^2))$ cannot deliver an integer sum as its denominator contains $p$. Here are these intervals for primes below $100$:

3 [7, 9)
5 [11, 25)
7 [29, 43)
11 [23, 67)
13 [53, 79)
17 [103, 137)
19 [191, 229)
23 [47, 139)
29 [59, 233)
31 [311, 373)
37 [149, 223)
41 [83, 739)
43 [173, 431)
47 [283, 659)
53 [107, 743)
59 [709, 827)
61 [367, 733)
67 [269, 1609)
71 [569, 853)
73 [293, 439)
79 [317, 1423)
83 [167, 499)
89 [179, 1069)
97 [389, 971)

As we can see primes 5, 11, 29, 41, 67 alone cover the interval $[11, 1609)$, while others provide extensive backup support. Such a pattern will likely continue to cover all integers above $11$. However I'm not sure whether this observation can be justified theoretically without relying on unproved conjectures.

Here is some computational evidence that $n\in\{1,2,4\}$ are the only $n$ that deliver an integer sum. 

For an odd prime $p$, let $a_p < b_p$ denote two smallest even positive integers such that $a_pp+1$ and $b_pp+1$ are prime. Then $n\in \big[a_pp+1,\min\{b_pp+1,p^2\}\big)$ cannot deliver an integer sum as its denominator will necessarily contain $p$. Here are these intervals for primes $p<100$:

3 [7, 9)
5 [11, 25)
7 [29, 43)
11 [23, 67)
13 [53, 79)
17 [103, 137)
19 [191, 229)
23 [47, 139)
29 [59, 233)
31 [311, 373)
37 [149, 223)
41 [83, 739)
43 [173, 431)
47 [283, 659)
53 [107, 743)
59 [709, 827)
61 [367, 733)
67 [269, 1609)
71 [569, 853)
73 [293, 439)
79 [317, 1423)
83 [167, 499)
89 [179, 1069)
97 [389, 971)

As we can see primes 5, 11, 29, 41, 67 alone cover the interval $[11, 1609)$, while others provide extensive backup support. Such a pattern will likely continue to cover all integers above $11$. However I'm not sure whether this observation can be justified theoretically without relying on unproved conjectures.

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Max Alekseyev
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Here is some computational evidence for finiteness of such $n$. For an odd prime, let $a_p < b_p$ denote two smallest even positive integers such that $a_pp+1$ and $b_pp+1$ are prime. Then $n\in [a_pp+1,\min(b_pp+1,p^2))$ cannot deliver an integer sum as its denominator contains $p$. Here are these intervals for primes below $100$:

3 [7, 9)
5 [11, 6125)
7 [29, 21143)
11 [23, 33167)
13 [53, 85979)
17 [103, 1871137)
19 [191, 3877229)
23 [47, 1151139)
29 [59, 1741233)
31 [311, 9859373)
37 [149, 6143223)
41 [83, 3527739)
43 [173, 7741431)
47 [283, 13537659)
53 [107, 6043743)
59 [709, 42953827)
61 [367, 22571733)
67 [269, 184931609)
71 [569, 40471853)
73 [293, 22193439)
79 [317, 254391423)
83 [167, 15107499)
89 [179, 176231069)
97 [389, 37831971)

As we can see primes 5, 2311, 5929, 41, 67 alone cover the interval $[11, 42953)$$[11, 1609)$, while others provide extensive backup support. Such a pattern will likely continue to cover all integers above $11$. However I'm not sure whether this observation can be justified theoretically without relying on unproved conjectures.

Here is some computational evidence for finiteness of such $n$. For an odd prime, let $a_p < b_p$ denote two smallest even positive integers such that $a_pp+1$ and $b_pp+1$ are prime. Then $n\in [a_pp+1,\min(b_pp+1,p^2))$ cannot deliver an integer sum as its denominator contains $p$. Here are these intervals for primes below $100$:

3 [7, 9)
5 [11, 61)
7 [29, 211)
11 [23, 331)
13 [53, 859)
17 [103, 1871)
19 [191, 3877)
23 [47, 1151)
29 [59, 1741)
31 [311, 9859)
37 [149, 6143)
41 [83, 3527)
43 [173, 7741)
47 [283, 13537)
53 [107, 6043)
59 [709, 42953)
61 [367, 22571)
67 [269, 18493)
71 [569, 40471)
73 [293, 22193)
79 [317, 25439)
83 [167, 15107)
89 [179, 17623)
97 [389, 37831)

As we can see primes 5, 23, 59 alone cover the interval $[11, 42953)$, while others provide extensive backup support. Such a pattern will likely continue to cover all integers above $11$. However I'm not sure whether this observation can be justified theoretically without relying on unproved conjectures.

Here is some computational evidence for finiteness of such $n$. For an odd prime, let $a_p < b_p$ denote two smallest even positive integers such that $a_pp+1$ and $b_pp+1$ are prime. Then $n\in [a_pp+1,\min(b_pp+1,p^2))$ cannot deliver an integer sum as its denominator contains $p$. Here are these intervals for primes below $100$:

3 [7, 9)
5 [11, 25)
7 [29, 43)
11 [23, 67)
13 [53, 79)
17 [103, 137)
19 [191, 229)
23 [47, 139)
29 [59, 233)
31 [311, 373)
37 [149, 223)
41 [83, 739)
43 [173, 431)
47 [283, 659)
53 [107, 743)
59 [709, 827)
61 [367, 733)
67 [269, 1609)
71 [569, 853)
73 [293, 439)
79 [317, 1423)
83 [167, 499)
89 [179, 1069)
97 [389, 971)

As we can see primes 5, 11, 29, 41, 67 alone cover the interval $[11, 1609)$, while others provide extensive backup support. Such a pattern will likely continue to cover all integers above $11$. However I'm not sure whether this observation can be justified theoretically without relying on unproved conjectures.

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Max Alekseyev
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